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如何在 Pocket Option 中验证帐户

The problem, as being explained in another 如何在 Pocket Option 中验证帐户 answer, is that onClick on a React component (contrary to native DOM element like or ) is treated as passing of component property, and not of a DOM event handler. And as most likely your component doesn't declare onClick property, that property value simply gets lost.

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This USB driver (STSW-LINK009) is for ST-LINK/V2, ST-LINK/V2-1 and STLINK-V3 boards and derivatives (STM8/STM32 discovery boards, STM8/STM32 evaluation boards and STM32 Nucleo boards). It declares to the system the USB interfaces possibly provided by 如何在 Pocket Option 中验证帐户 the ST-LINK: ST Debug, Virtual COM port and ST Bridge interfaces. The driver must be installed prior to connecting the device, in order to have a successful enumeration.

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The starting state of the menu will appear collapsed on smaller screens, and will appear non-collapsed on larger screens. When toggled using the button below, the menu will change.

Make sure to keep all page content within the #page-content-wrapper . The top navbar is optional, and just for demonstration. Just create an element with the #sidebarToggle ID which 如何在 Pocket Option 中验证帐户 如何在 Pocket Option 中验证帐户 will toggle the menu when clicked.

React onClick event on component

I have a React component called that 如何在 Pocket Option 中验证帐户 如何在 Pocket Option 中验证帐户 has many child s (another React component). I want to be able to declare an onClick event on each from within . I have tried doing the following:

Needless to say, I do not get any "Clicked!" coming up in my console. The React 如何在 Pocket Option 中验证帐户 inspector in Chrome indicates that an onClick event is registered, with the above function body as it should be.

I conclude, therefore, that I can't register onClick events on the actual tags (I'如何在 Pocket Option 中验证帐户 m not sure why this is, however). How do I go about achieving this otherwise?

2 Answers 2

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This depends on your SensorItem 如何在 Pocket Option 中验证帐户 component's definition. Because SensorItem isn't a native DOM element but, like you said, another React component, onClick as defined here is simply a property of that component. What you need to do is, inside of the SensorItem component pass the onClick prop to an DOM component's onClick event:

Got 如何在 Pocket Option 中验证帐户 it, I had thought perhaps that a component automatically passed on any events to the main DOM Node ( getDOMNode() ), but there's no reason this should be the case.

I had thought, assumed, was certain that those geniuses at Facebook would've thought it would be convenient. Not convenient enough, I 如何在 Pocket Option 中验证帐户 guess.

To add to that, you can pass through all props to the main DOM Node fairly easily with argument destructuring syntax like this: ``` 如何在 Pocket Option 中验证帐户 const SensorItem = (<. props>) => < return (

> .
); > ``` That makes it future-proof if you need to add onDoubleClick, onKeyDown, etc.

Problem

The problem, as being explained in another answer, is that onClick on a React component (contrary to native DOM element like or

) is treated as passing of component property, and not of a DOM event handler. And as most likely your component doesn't declare onClick property, that property value simply gets lost.

Solution

The most straightforward solution is to add onClick property explicitly on SensorItem component, then pass it to the root DOM element of that component:

But the solution that usually works best for me is to group all the undefined component's properties using object destructuring notation, then pass them all to the root 如何在 Pocket Option 中验证帐户 DOM element within that component. This way you can 如何在 Pocket Option 中验证帐户 pass onClick , onHover , className etc. without needing to define separate properties for each one of them:

No matter which of the two approaches you use, the handler will now work, as it'll now be attached to the root DOM element of SensorItem :